# What's the Current Day Number?

## Today Saturday, November 27, 2021 is ...

### Day 331

Day of the year is a number between 1 and 365 (in 2021), January 1 is day 1.
After today 34 days are remaining in this year.

There is also another less-used format: the 'ISO day of year' numbers, this is a number between 1 and 371, day 1 of the year is Monday of the first ISO week (where the first Thursday of the new year is in week 1).

## Programming routines

### Microsoft Excel

Calculate today's day-number, starting from the day before Jan 1, so that Jan 1 is day 1.

```=TODAY()-DATE(YEAR(TODAY()),1,0)
or, for any date entered in cell A1, calculate the corresponding day-number in that date’s year:
=A1-DATE(YEAR(A1),1,0)```

`=DATEDIF(CONCAT("1-1-";year(now()));today();"D")+1`

Calculates the difference between Jan 1 and today (=days past) then add 1 for today's daynumber. (Your date format (1-1-year) may be different)

### LibreOffice Calc:

`=ROUNDDOWN(DAYS(NOW(),DATE(YEAR(NOW()),1,1))) + 1`

### PHP

`\$dayNumber = date("z") + 1; `
You can use an epoch to find other day numbers:
`date("z", epoch) + 1`
date("z") starts counting from 0 (0 through 365)!

### Python

```from datetime import datetime
day_of_year = datetime.now().timetuple().tm_yday```

### PERL

```use Time::Piece;
my \$day_of_year = localtime->yday + 1;

# ... or ...
my \$day_of_year = (localtime) +1;

# ... or (if you really want to use POSIX) ...
use POSIX;
my \$day_of_year = POSIX::strftime("%j", time);```

Replace time with other epochs for other days.

### MySQL

`SELECT DAYOFYEAR(NOW())`
Day number between 1 and 366. Replace now() with other dates eg.:
`SELECT DAYOFYEAR('2021-02-20');`

### Oracle

```select to_char(sysdate, 'DDD') from dual
select to_char(to_date('2021-02-20','YYYY-MM-DD'), 'DDD') from dual```

### Delphi

```using DateUtils, SysUtils;
DayOfTheYear(Date);```

### Microsoft Access

`DatePart("y", Now())`

### Visual Basic (VB.NET)

`Dim dayOfYear As Integer = DateTime.Now.DayOfYear`

### JavaScript

```var today = new Date();
Math.ceil((today - new Date(today.getFullYear(),0,1)) / 86400000);
```

Or add a 'Day of Year' method to the date object:

```Date.prototype.getDOY = function() {
var onejan = new Date(this.getFullYear(),0,1);
return Math.ceil((this - onejan) / 86400000);
}
var today = new Date();
var daynum = today.getDOY();
```

### Java

`LocalDate.now().getDayOfYear();`

### Unix/Linux

`date +%j`

### ColdFusion

`#dayofyear(now())# `

### Objective C

```int currentDay;
dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:@"D"];
date = [NSDate date];
currentDay = [[dateFormatter stringFromDate:date] intValue];
```

### C++

Read the comment below by Mmars.

### C#

`int iDayOfYear = System.DateTime.UtcNow.DayOfYear;`

### R

`format(Sys.Date(), "%j")`

### Ruby

```time = Time.new
puts time.yday```

### Powershell

```\$DayOfYear = (Get-Date).DayofYear
Write-Host \$DayOfYear```

### LiveCode

```on mouseUp
put "January 1," && the last word of the long date into firstDayofYear --append current year
convert firstDayofYear to seconds -- from Jan 1, 1970 to first day of this year
put the long date into currentDay
convert currentDay to seconds -- from Jan 1, 1970 GMT to today
put currentDay - firstDayofYear into totalSeconds
answer the round of (totalSeconds / (60*60*24)) + 1 --display total days in dialog box
end mouseUp```
Or:
```on mouseUp
end mouseUp

function DayOfYear
put the short date into currentDate
convert currentDate to dateItems --list of date elements separated by commas
put item 1 of currentDate into year
put item 2 of currentDate into month
put item 3 of currentDate into day
put floor (275 * month / 9) into N1
put floor ( (month + 9) / 12) into N2
put (1 + floor ( (year - 4 * floor (year / 4) + 2) / 3) ) into N3
put N1 - (N2 * N3) + day - 30 into N
return N
end DayOfYear

function floor pNumber -- LiveCode has no built-in floor() function
put Round (pNumber) into theInteger
if theInteger > pNumber then
put theInteger - 1 into theInteger
end if
return theInteger
end floor```

### T-SQL (Transact-SQL)

`SELECT DATEPART(DAYOFYEAR, SYSDATETIME())`
or
```SELECT datediff(day,CAST(datepart(year,getdate()) AS CHAR(4)) + '-01-01',getdate()+1)
AS number_of_today```

### Go (golang)

`day := time.Now().YearDay()`

### Matlab

`dayNumber = today-datenum(['1-Jan-' year(today)])+1`

### Powerbuilder

Read the comment below by Danny Cruz.